Created
June 8, 2020 23:12
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// assuming our adjacency matrix is {A: [B, C, D], B:[D, E], ...} | |
// assuming that our vertices have the following properties: | |
// 1. (boolean) visited | |
// ASSUME graph is a DAG | |
function topSort(adj) { | |
// get the number of vertices in the DAG | |
let numV = Object.keys(adj).length; | |
// initialize resulting array | |
let res = Array.new(numV).fill(null); | |
// get the last index of the array | |
let openIdx = res.length - 1; | |
// have a dfs helper function | |
function dfs(vertex) { | |
// base case | |
// if the vertex has already been processed, just ignore it | |
if(v.visited) return; | |
// get the neighbors | |
let neighbors = adj[vertex]; | |
// loop through the neighbors | |
for(let v of neighbors) { | |
// do a DFS if the vertex hasn't been visited | |
if(!v.visited) dfs(v); | |
} | |
// mark the vertex as visited | |
vertex.visited = true; | |
// add the vertex to the rightmost open spot in the array | |
res[openIdx] = vertex; | |
// move the index to the next open spot on the left | |
openIdx -= 1; | |
return; | |
} | |
// get the vertices | |
let vertices = Object.keys(adj); | |
// do a DFS on all the vertices | |
for(let v of vertices) { | |
if(!v.visited) dfs(v); | |
} | |
// return the resulting array | |
return res; | |
} |
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