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March 3, 2018 21:48
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Minify for loops
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| for (let i = 0; i < board.length; i++) { | |
| returnBoard[i] = [] | |
| for (let j = 0; j < board[i].length; j++) { | |
| let neighborCount = getCellNeighborCount(i, j) | |
| if (board[i][j] === 1) { | |
| if (neighborCount > 1 && neighborCount < 4) { | |
| returnBoard[i][j] = 1 | |
| } else { | |
| returnBoard[i][j] = 0 | |
| } | |
| } else { | |
| returnBoard[i][j] = neighborCount === 3 ? 1 : 0 | |
| } | |
| } | |
| } |
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