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2D Lyapunov in Python using ANSI terminal colors
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#!/usr/bin/env python3 | |
import math | |
from sys import stdout | |
import shutil | |
w,h = shutil.get_terminal_size() | |
a0 = 3.0 | |
a1 = 4.0 | |
b0 = 3.5 | |
b1 = 4.0 | |
sequence = "AABAB" | |
settle = 10 | |
iters = 100 | |
scale = 2.0/(iters) | |
colors = 18 | |
def plot(c): | |
r = 0 if c<0 else c if c<6 else 5 | |
g = 0 if c<6 else c-6 if c<12 else 5 | |
b = -c%5 if c<0 else 0 if c<12 else c-12 if c<18 else 5 | |
stdout.write(f"\033[48;5;{16+36*r+6*g+b}m ") | |
l = len(sequence) | |
for y in range(h): | |
b = b0 + (b1-b0) * y / h | |
for x in range(w): | |
a = a0 + (a1-a0) * x / w | |
z = 0 | |
c = 0.5 | |
for i in range(iters): | |
r = a if sequence[i % l]=='A' else b | |
c = r * c * (1 - c) | |
if i > settle: | |
r = abs(r - 2.0 * r * c) | |
z = z + math.log10(r) | |
plot(int(-z * scale * colors)) | |
stdout.write("\033[0m\n") |
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