Created
July 7, 2024 09:10
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Simple parenthesis parser.
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| #include <stdio.h> | |
| #include <string.h> | |
| #include <stdlib.h> | |
| void parse(char* in); | |
| void main(){ | |
| char* in="12+(13-22)+(2-4/(33-456))"; | |
| parse(in); | |
| } | |
| void parse(char* in){ | |
| int level=0; | |
| int begin=0; | |
| int end=0; | |
| puts(in); | |
| for(int i=0;i<strlen(in);i++){ | |
| //printf("%d %c\n", i, in[i]); | |
| if (in[i] == '('){ | |
| if(level == 0){ | |
| begin=i; | |
| } | |
| level++; | |
| continue; | |
| } else if (in[i] == ')'){ | |
| if(level == 1){ | |
| char* n = strndup(in+begin+1, i-begin-1); | |
| parse(n); | |
| } | |
| level--; | |
| continue; | |
| } | |
| } | |
| if(begin == 0) { | |
| // run expression and return some stuff. | |
| } | |
| } |
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