Created
July 21, 2015 18:22
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| #include "fcgi_stdio.h" | |
| #include <unistd.h> | |
| void print_numbers( double* numbers, int n) { | |
| for (int i=0;i<n;i++) { | |
| printf("%s%.4lf",i>0?",":"",numbers[i]); | |
| } | |
| printf("\r\n"); | |
| } | |
| void do_header() { | |
| printf("Content-type: text/plain\r\n\r\n" | |
| "pid: %d\r\n", getpid()); | |
| } | |
| int main (int argc, char** argv) { | |
| double x[12] = { 36.7858,68.0403,87.9978,106.0944,127.2410,159.4316,216.7858,248.0403,267.9978,286.0944,307.2410,339.4316 }; | |
| while (FCGI_Accept() >= 0) { | |
| do_header( ); | |
| print_numbers( x, 12 ); | |
| } /* while */ | |
| return 0; | |
| } |
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See http://stackoverflow.com/questions/31525028/printf-swallowing-bytes-in-fcgi-mode
Output using the format specifier %lf will not be performed by programs in fastcgi. When changing the %.4lf to %.4f in the above example, the doubles will be printed as expected.