Created
April 29, 2013 07:16
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Split a sequence into groups of `n` consecutive elements each, with 1..n items in the last group.
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| function range(n) { | |
| return Array.apply(null, Array(n)).map(function (_, i) { return i }) | |
| } | |
| function ntuples(n, xs) { | |
| return range(Math.ceil(xs.length / n)).map(function (i) { | |
| return xs.slice(i * n, i * n + n) | |
| }) | |
| } | |
| ntuples(2, 'abc') //=> ['ab', 'c'] | |
| ntuples(2, 'abcdef') //=> ['ab', 'cd', 'ef'] | |
| ntuples(3, [1, 2, 3, 4, 5, 6, 7]) //=> [[1, 2, 3], [4, 5, 6], [7]] |
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The more I look at this, the more I like its simplicity.