Created
February 23, 2017 07:08
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Minimal naive Sudoku solver
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sstr = ''' | |
71 4 | |
6 8 | |
3 4 16 | |
6 1 | |
3 8 | |
1 7 2 | |
8 9 | |
53 4 2 | |
4 1 9 ''' | |
sudoku1_s8 = ''' | |
9 65 4 1 | |
5 83 9 | |
4 26 3 | |
36 751 | |
54 2 3 68 | |
796 45 | |
6 57 8 | |
3 86 7 | |
7 2 49 6''' | |
sudoku_sz_1 = ''' | |
3596 412 | |
67 | |
82 6 | |
216 5483 | |
874361952 | |
248761 | |
621 | |
8132675 | |
621 783 ''' | |
class State(object): | |
def __init__(self, sstr): | |
cnt = 0 | |
state = [dict([(str(i+1),1) for i in range(9)]) for x in range(81)] | |
for line in sstr.split('\n'): | |
if len(line)>1: | |
for c in line: | |
if c in '123456789': | |
state[cnt] = c | |
cnt+=1 | |
self.state = state | |
def row(self, n): | |
row = self.state[n*9:(n+1)*9] | |
return row | |
def col(self, n): | |
col = [self.state[9*x+n] for x in range(9)] | |
return col | |
def sq(self, n): | |
row = n/3 | |
col = n%3 | |
sq = [self.state[9*(3*row+j) + 3*col+i] for j in range(3) for i in range(3)] | |
return sq | |
def eliminate(self, elems): | |
fixeds = [e for e in elems if type(e) != dict] | |
for f in fixeds: | |
for e in elems: | |
if type(e) == dict and f in e: | |
del e[f] | |
def clean(self): | |
for e, x in enumerate(self.state): | |
if type(x) == dict and len(x) == 1: | |
self.state[e] = x.keys()[0] | |
def elimround(self): | |
for fun in [self.row, self.col, self.sq]: | |
for i in range(9): | |
elems = fun(i) | |
self.eliminate(elems) | |
self.clean() | |
def __str__(self): | |
sstr = '' | |
cnt = 0 | |
for e in self.state: | |
if type(e) == dict: | |
sstr+=' ' | |
else: | |
sstr+=e | |
cnt+=1 | |
if cnt%9==0: | |
sstr+='\n' | |
return sstr | |
s = State(sudoku_sz_1) | |
print s | |
for i in range(10): | |
s.elimround() | |
print s | |
print s.state |
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