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| /* | |
| You are given 2 numbers as strings, and you need to sum them assuming that you can't simply parse them as integers | |
| cause the numbers may be too big to be stored as an integer | |
| Return the sum as a string | |
| */ | |
| function sumStrings(str1, str2) { | |
| const parsedDigits1 = str1 | |
| .split('') | |
| .reverse() | |
| .map((digit) => parseInt(digit)); | |
| const parsedDigits2 = str2 | |
| .split('') | |
| .reverse() | |
| .map((digit) => parseInt(digit)); | |
| const biggerNumber = parsedDigits1.length > parsedDigits2.length ? [...parsedDigits1] : [...parsedDigits2]; | |
| const smallerNumber = parsedDigits2.length < parsedDigits1.length ? [...parsedDigits2] : [...parsedDigits1]; | |
| const digitsSums = biggerNumber.map((digit, index) => { | |
| return digit + (smallerNumber[index] >= 0 ? smallerNumber[index] : 0); | |
| }); | |
| return processCarrys(digitsSums).reverse().join(''); | |
| } | |
| function processCarrys(digitsSums) { | |
| const digitSumsCopy = [...digitsSums]; | |
| return digitSumsCopy.map((sum, index) => { | |
| if (sum >= 10 && digitSumsCopy[index + 1] >= 0) { | |
| digitSumsCopy[index + 1] += 1; | |
| return sum % 10; | |
| } | |
| return sum; | |
| }); | |
| } | |
| function test(str1, str2, solution) { | |
| const res = sumStrings(str1, str2) | |
| const isCorrect = res === solution ? "Correct" : "Incorrect" | |
| console.log(`${str1} + ${str2} = ${res} \t=>\t${isCorrect}, expected ${solution}`) | |
| } | |
| test('1', '1', '2') | |
| test('9', '1', '10') | |
| test('999', '2', '1001') | |
| test('10001', '1', '10002') | |
| test('1', '10001', '10002') | |
| test('10009', '10001', '20010') | |
| test('299', '12', '311') |
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