Created
June 11, 2011 04:38
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| from string import digits | |
| x = ["1a", "2b", "2b", "3c", "5e"] | |
| #the clearest, most basic way I can think of | |
| numbers = {} | |
| for i in x: | |
| first = i[0] | |
| if first in digits: | |
| if first in numbers: | |
| numbers[first] += 1 | |
| else: | |
| numbers[i[0]] = 1 | |
| for i in digits: | |
| if i not in numbers: | |
| print "0 %s's" % (i) | |
| else: | |
| print "%s %s's" % (numbers[i], i) | |
| print "=================" | |
| #here's one way to simplify it: | |
| # http://docs.python.org/library/collections.html#collections.Counter | |
| from collections import Counter | |
| numbers = Counter() | |
| for i in x: | |
| if i[0] in digits: | |
| numbers[i[0]] += 1 | |
| #a counter's value defaults to 0, so we don't need to check if we've set it yet or not | |
| for i in digits: | |
| print "%s %s's" % (numbers[i], i) | |
| print "=================" | |
| #here's another | |
| # (don't do this, it's here for neato value :) | |
| print {i:sum(j[0]==i for j in x) for i in map(str, range(10))} | |
| print "=================" | |
| #the equivalent of @agnellvj's answer: | |
| numbers = {} | |
| for i in x: | |
| numbers[i[0]] = numbers.setdefault(i[0], 0) + 1 | |
| for i in digits: | |
| if i not in numbers: | |
| print "0 %s's" % (i) | |
| else: | |
| print "%s %s's" % (numbers[i], i) |
"from string import digits" is letting you skip the step of breaking each array element into a list, no?
nope, "from string import digits" just imports the string '0123456789', there's no need to break each array element into a list
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python looks messy.... :)