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April 11, 2018 08:57
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Project Euler - Problem 6 - Sum square difference
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/* | |
Project_6.cpp : Sum square difference | |
The sum of the squares of the first ten natural numbers is, | |
1^2 + 2^2 + ... + 10^2 = 385 | |
The square of the sum of the first ten natural numbers is, | |
(1 + 2 + ... + 10)^2 = 55^2 = 3025 | |
Hence the difference between the sum of the squares of the first ten natural numbers | |
and the square of the sum is 3025 − 385 = 2640. | |
Find the difference between the sum of the squares of | |
the first one hundred natural numbers and the square of the sum. | |
*/ | |
#include <iostream> | |
using namespace std; | |
int main() | |
{ | |
int sum1 = 0, sum2 = 0; | |
for (int i = 1; i < 101; i++) | |
{ | |
sum1 += i * i; | |
} | |
for (int j = 0; j < 101; j++) | |
{ | |
sum2 += j; | |
} | |
cout << "Result is:\n" << sum2 * sum2 << " - " << sum1 << " = " << | |
(sum2*sum2) - sum1 << endl; | |
return 0; | |
} |
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