Created
August 9, 2023 13:20
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leetcode1190 Reverse Substrings Between Each Pair of Parentheses, mostly from ravensmove.com/
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| class Solution(object): | |
| def reverseParentheses(s): | |
| if not s: | |
| return '' | |
| arr = [] | |
| for char in s: | |
| if char == ')': | |
| combine_str = '' | |
| while arr and arr[-1] != '(': | |
| elem = arr.pop()[::-1] | |
| combine_str += elem | |
| arr.pop() | |
| arr.append(combine_str) | |
| else: | |
| arr.append(char) | |
| return "".join(arr) | |
| # answer 1 | |
| s = "(abcd)" | |
| print(Solution.reverseParentheses(s)) | |
| # answer 2 | |
| s = "(u(love)i)" | |
| print(Solution.reverseParentheses(s)) | |
| # answer 3 | |
| s = "(ed(et(oc))el)" | |
| print(Solution.reverseParentheses(s)) | |
| # answer 4 | |
| s = "a(bcdefghijkl(mno)p)q" | |
| print(Solution.reverseParentheses(s)) |
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