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October 6, 2018 11:41
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This will solve the "crack the code" riddle at https://www.instagram.com/p/BoeZ7IvC5gM/ (its 042)
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| import java.util.ArrayList; | |
| public class CrackTheCode2 { | |
| public static void main(String[] args) { | |
| int totalPoss = 0; | |
| for (int a = 0; a < 10; a++) { | |
| for (int b = 0; b < 10; b++) { | |
| for (int c = 0; c < 10; c++) { | |
| if (wellPlaced(a, b, c, 6, 8, 2) != 1) continue; | |
| if (wrongPlaced(a, b, c, 6, 1, 4) != 1) continue; | |
| if (wrongPlaced(a, b, c, 2, 0, 6) != 2) continue; | |
| if (wrongPlaced(a, b, c, 7, 3, 8) != 0) continue; | |
| if (wrongPlaced(a, b, c, 7, 8, 0) != 1) continue; | |
| totalPoss++; | |
| System.out.println(numberFromDigits(a, b, c)); | |
| } | |
| } | |
| } | |
| System.out.println(); | |
| System.out.println("Total: " + totalPoss); | |
| } | |
| public static int wrongPlaced(int a, int b, int c, int a1, int b1, int c1) { | |
| if (wellPlaced(a, b, c, a1, b1, c1) != 0) return -1; | |
| ArrayList<Integer> digits = new ArrayList<>(); | |
| digits.add(a); | |
| digits.add(b); | |
| digits.add(c); | |
| int count = 0; | |
| if (digits.contains(a1)) count++; | |
| if (digits.contains(b1)) count++; | |
| if (digits.contains(c1)) count++; | |
| return count; | |
| } | |
| public static int wellPlaced(int a, int b, int c, int a1, int b1, int c1) { | |
| int count = 0; | |
| if (a == a1) count++; | |
| if (b == b1) count++; | |
| if (c == c1) count++; | |
| return count; | |
| } | |
| public static String numberFromDigits(int a, int b, int c) { | |
| return String.valueOf(a) + String.valueOf(b) + String.valueOf(c); | |
| } | |
| } |
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