Created
June 23, 2014 14:43
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| #include <iostream> | |
| template <typename VAL, typename FUNC> | |
| inline typename std::result_of<FUNC(const VAL&)>::type | |
| invoke(const VAL& trg, FUNC func) | |
| { | |
| return func(trg); | |
| } | |
| template <typename VAL, typename FUNC> | |
| inline typename std::result_of<FUNC(VAL&)>::type | |
| invoke(VAL& trg, FUNC func) | |
| { | |
| return func(trg); | |
| } | |
| struct IsEven | |
| { | |
| typedef bool reuslt_type; | |
| bool operator()(const int& n) { return n % 2 == 0; } | |
| }; | |
| struct Increment | |
| { | |
| typedef bool reuslt_type; | |
| void operator()(int& n) { ++n; } | |
| }; | |
| int main() | |
| { | |
| int a = 2; | |
| std::cout << invoke(a, IsEven()) << std::endl; | |
| invoke(a, Increment()); | |
| std::cout << a << std::endl; | |
| return 0; | |
| } |
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VS2013のエラーメッセージ
「error C2664: 'void Increment::operator ()(int &)' : 引数 1 を 'const int' から 'int &' へ変換できません。」