Created
December 16, 2018 10:11
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pub fn solve_part1_fast2(input: &str) -> usize { | |
let mut lines = input.lines(); | |
let mut ret = 0; | |
let lookup : Vec<u32> = vec![38195, 38195, 38195, 38195, 4403, 13107, 54743, 48059, 5393, 39219, 21847, 39355, 37137, 47411, 21973, 39355, 4403, 13107, 22391, 48059, 46899, 46899, 46899, 46899, 5427, 47411, 22391, 48059, 37171, 47923, 22007, 48059, 5427, 13107, 22391, 39867, 5939, 14195, 55287, 48059, 38773, 38773, 38773, 38773, 38193, 47923, 21973, 39867, 37171, 47923, 22519, 48059, 45875, 47923, 57343, 48059, 38193, 47547, 22519, 48059, 46521, 46521, 46521, 46521]; | |
while let Some(line) = lines.next() { | |
if line.is_empty() || line.as_bytes()[0] != b'B' { break; } | |
let before = line.as_bytes(); | |
let op = lines.next().unwrap().as_bytes(); | |
let after = lines.next().unwrap().as_bytes(); | |
let a_start = if op[1] == b' ' { 2 } else { 3 }; | |
let a = (op[a_start] - b'0') as usize; | |
let b = (op[a_start+2] - b'0') as usize; | |
let o = (op[a_start+4] - b'0') as usize; | |
let afo = (after[9 + o*3] - b'0') as usize; | |
let rea = (before[9 + a*3] - b'0') as usize; | |
let reb = (before[9 + b*3] - b'0') as usize; | |
ret += ((lookup[(a<<4) | (b<<2) | rea] >> ((reb<<2) | afo)) & 0x01) as usize; | |
lines.next(); | |
} | |
ret | |
} |
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