Created
January 2, 2017 14:59
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Gulp execute script PHP
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| var exec = require('child_process').exec | |
| gulp.task('update-templates', function(){ | |
| exec('php scripts/update-html.php', function (err, stdout, stderr) { | |
| console.log(stdout) | |
| console.log(stderr) | |
| }) | |
| }) | |
| gulp.task('default',['update-templates']) |
Acually, it will freeze. You need to tell the process to it has finished.
gulp.task('update-templates', function(imdone){
exec('php scripts/update-html.php', function (err, stdout, stderr) {
console.log(stdout)
console.log(stderr)
imdone();
})
})
@seigieu thanks for your contribution.
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Nice