Created
September 5, 2019 07:39
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Flatten a nested dictionary in python
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def flatten(nested, column_names): | |
all_dicts = [] | |
final_result = {} | |
index = 0 | |
def recurse(data): | |
for k, v in data.items(): | |
final_result = {} | |
if isinstance(v, dict): | |
if any(isinstance(i,dict) for i in v.values()): | |
recurse(v) | |
else: | |
final_result.update(v) | |
all_dicts.append(final_result.copy()) | |
else: | |
final_result[k]=v | |
all_dicts.append(final_result.copy()) | |
recurse(nested) | |
return all_dicts | |
def flatten2(nested, column_names): | |
all_dicts = [] | |
final_result = {} | |
index = 0 | |
def recurse(data, existing = []): | |
for k, v in data.items(): | |
final_result = {} | |
if isinstance(v, dict): | |
if any(isinstance(i,dict) for i in v.values()): | |
existing.append(k) | |
recurse(v, existing=existing) | |
else: | |
final_result.update(v) | |
final_result.update(zip(column_names[:len(existing)], existing)) | |
all_dicts.append(final_result.copy()) | |
else: | |
final_result[k]=v | |
final_result.update(zip(column_names[:len(existing)], existing)) | |
all_dicts.append(final_result.copy()) | |
recurse(nested) | |
return all_dicts | |
a = { | |
'foo': { | |
'cat': {'name': 'Hodor', 'age': 7}, | |
'dog': {'name': 'Mordor', 'age': 5}, | |
}, | |
'bar': { | |
'rat': {'name': 'Izidor', 'age': 3}, | |
'ratv': {'nameb': 'Izidor', 'age': 3}, | |
}, | |
'baz': 'woops', | |
} | |
print(flatten(a, ['foobar', 'animal'])) |
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