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Nested numbers Quiz (6-10) of Udacity FEWD
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| /* | |
| * Programming Quiz: Nested Numbers (6-10) | |
| * | |
| * - The `numbers` variable is an array of arrays. | |
| * - Use a nested `for` loop to cycle through `numbers`. | |
| * - Convert each even number to the string "even" | |
| * - Convert each odd number to the string "odd" | |
| */ | |
| var numbers = [ | |
| [243, 12, 23, 12, 45, 45, 78, 66, 223, 3], | |
| [34, 2, 1, 553, 23, 4, 66, 23, 4, 55], | |
| [67, 56, 45, 553, 44, 55, 5, 428, 452, 3], | |
| [12, 31, 55, 445, 79, 44, 674, 224, 4, 21], | |
| [4, 2, 3, 52, 13, 51, 44, 1, 67, 5], | |
| [5, 65, 4, 5, 5, 6, 5, 43, 23, 4424], | |
| [74, 532, 6, 7, 35, 17, 89, 43, 43, 66], | |
| [53, 6, 89, 10, 23, 52, 111, 44, 109, 80], | |
| [67, 6, 53, 537, 2, 168, 16, 2, 1, 8], | |
| [76, 7, 9, 6, 3, 73, 77, 100, 56, 100] | |
| ]; | |
| // your code goes here | |
| for (var row= 0; row < numbers.length; row++) { | |
| for (col= 0; col < numbers[row].length; col++) { | |
| if ((numbers[row][col]%2) === 0) { | |
| numbers[row][col]= "even" | |
| } | |
| else numbers[row][col]= "odd"; | |
| } | |
| } |
add this ;
in line 27
Make sure you line 25 into this: for (var col= 0; col < numbers[row].length; col++) {
This is a correct code:
for (var r = 0; r < numbers.length; r++) {
for (var c = 0; c < numbers[r].length; c++){
if (numbers[r][c] % 2 === 0) {
numbers[r][c] = "even";
}
else {
numbers[r][c] = "odd";
}
console.log(numbers[r][c])
}
}
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Feedback: Your answer passed all our tests! Awesome job!