Created
October 6, 2016 23:19
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Yet another turtlewalk of the Thue-Morse Sequence, creating the Koch-Curve.
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// @bitcraftlab 2016 | |
boolean animate = true; | |
int dir = 1; | |
int iter = 5; | |
int n = 0; | |
int steps; | |
void setup() { | |
size(640, 400); | |
}; | |
void draw() { | |
steps = 2 << (2*(iter-1)); | |
float d = 1024.0 / pow(3, iter); | |
background(255); | |
strokeWeight(d/4); | |
translate(150, 240); | |
rotate(radians(-120)); | |
for (int i = 0; i < n; i++) { | |
// calculate thue morse digit | |
int b = i; | |
int r = 0; | |
while (b > 0) { | |
r = (r + b) % 2; | |
b /= 2; | |
} | |
// interprete the digit as turtle code | |
if (r == 0) { | |
rotate(radians(180)); | |
} else { | |
rotate(radians(-60)); | |
line(0, 0, d, 0); translate(d, 0); | |
} | |
} | |
n = animate && iter > 3 ? (n + dir + steps) % steps : steps; | |
} | |
void keyPressed() { | |
int i = iter; | |
switch(keyCode) { | |
case ' ': animate = !animate; break; | |
case UP: i--; break; | |
case DOWN: i++; break; | |
case LEFT: dir = -1; break; | |
case RIGHT: dir = 1; break; | |
} | |
i = constrain(i, 2, 6); | |
n *= pow(4, i - iter); | |
iter = i; | |
} |
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