Created
November 10, 2012 05:38
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jQuery dosen't like SVG css properties like 'fill' and 'stop-opacity' so, I wrote this to piggyback it with my own. @todo make this into a proper jQuery library.
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| /** | |
| * Function takes the style attribute and generates an object that | |
| * represents it's CSS properties. | |
| * @param styleAttr as String | |
| * @return style as Object | |
| */ | |
| getStyle = function(styleAttr) { | |
| var style = {}; | |
| styleAttr = styleAttr.split(';'); | |
| for (var i = 0; i < styleAttr.length; i++) { | |
| var property = styleAttr[i]; | |
| if (property == '') continue; | |
| property = property.split(':'); | |
| style[property[0]] = property[1]; | |
| } | |
| return style; | |
| } | |
| /** | |
| * Function takes an Object representing css and converts it into a | |
| * String for use as the 'style' HTML attribute. | |
| * @param style as Object | |
| * @return styleAttr as String | |
| */ | |
| getStyleAttr = function(style) { | |
| var styleAttr = ''; | |
| for (property in style) { | |
| styleAttr += property + ':' + style[property] + ';'; | |
| } | |
| return styleAttr; | |
| } | |
| // Example. | |
| var styleArr = $('svg stop').attr(style), | |
| style = getStyle(styleArr); | |
| style['stop-color'] = '#FF00FF'; | |
| $('svg stop').attr(style, getStyleAttr(style)); |
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