Thomas Miconi ThomasMiconi

See also https://github.com/uber-research/differentiable-plasticity

ThomasMiconi / gptlinreg.py

Last active April 11, 2023 19:05

GPT3.5 doing multiple linear regression in-context

	import os
	import openai
	import numpy as np
	import matplotlib.pyplot as plt

	# Load your API key from an environment variable or secret management service
	openai.api_key = os.getenv("OPENAI_API_KEY")

	NBTRAIN = 100
	NBTEST = 30

ThomasMiconi / prompt.txt

Last active April 11, 2023 06:03

Prompt for a novel arithmetic operation, following Zhou et al. 2022. See comments.

	Problem: 821`763=
	Explanation:
	The first number is 821, FN=[8,2,1]. The second number is 763, SN=[7,6,3]. Since FN [8,2,1] has 3 digits, SN [7,6,3] has 3 digits, thus the maximum number of digits is 3. In each subsequent step, we remove one number from the beginning of FN and one from the beginning of SN.
	Length of FN is 3. FN=[8,2,1]. Length of SN is 3. SN=[7,6,3]. FN[3]=8. SN[3]=7. C[3]=0. Since 8*7=56, 56%10=6, 56//10=5. Length of A is 1. Thus A=[6]. Since 5 is odd, we change the value of C. Since C[3]=0, C[2]=1.
	Length of FN is 2. FN=[2,1]. Length of SN is 2. SN=[6,3]. FN[2]=2. SN[2]=6. C[2]=1. Since 2*6=12, 12%10=2, 12//10=1. Length of A is 2. Thus A=[6,2]. Since 1 is odd, we change the value of C. Since C[2]=1, C[1]=0.
	Length of FN is 1. FN=[1]. Length of SN is 1. SN=[3]. FN[1]=1. SN[1]=3. C[1]=0. Since 1*3=4, 4%10=4, 4//10=0. Length of A is 3. Thus A=[6,2,4]. Since 0 is even, we do not change the value of C. Since C[1]=0, C[0]=0.
	There are no more digits and C[0]=0. Thus the process is complete. Sin