Created
November 27, 2018 10:10
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Golang 实现一个接口后 方法需要传数组怎么办
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| package main | |
| import ( | |
| "fmt" | |
| "reflect" | |
| ) | |
| type Aer interface { | |
| GetVal() string | |
| SetVal(int) | |
| } | |
| type AA struct { | |
| A int | |
| } | |
| func (a *AA) GetVal() string { | |
| return fmt.Sprintf("%v", a.A) | |
| } | |
| func (a *AA) SetVal(i int) { | |
| a.A += i | |
| } | |
| func arrAer(al []Aer) { | |
| for k, v := range al { | |
| fmt.Printf("k=>%v v=>%v vv=>%v\n", k, v, v.GetVal()) | |
| } | |
| } | |
| func aer(al Aer) { | |
| fmt.Printf("k=>%v v=>%v vv=>%v\n", al, al, al.GetVal()) | |
| } | |
| func ToAer(i interface{}) []Aer { | |
| ua := make([]Aer, 0) | |
| rv := reflect.ValueOf(i) | |
| if rv.Kind() != reflect.Slice { | |
| panic("not support type") | |
| } | |
| l := rv.Len() | |
| for i := 0; i < l; i++ { | |
| iv, ok := rv.Index(i).Interface().(Aer) | |
| if !ok { | |
| panic("not support type sub index") | |
| } | |
| ua = append(ua, iv) | |
| } | |
| for _, v := range ua { | |
| v.SetVal(4) | |
| } | |
| return ua | |
| } | |
| func main() { | |
| al := make([]*AA, 0) | |
| al = append(al, &AA{A: 1}) | |
| al = append(al, &AA{A: 2}) | |
| al = append(al, &AA{A: 3}) | |
| nal := ToAer(al) | |
| fmt.Println(al, nal) | |
| arrAer(nal) | |
| aer(al[0]) | |
| aer(al[1]) | |
| aer(al[2]) | |
| } |
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