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September 10, 2022 15:54
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3d dp concept chocolate pickup
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#include<bits/stdc++.h> | |
const int mod=-1e9+7; | |
int dp[50][50][50]; | |
int solve(int i,int j1,int j2,vector<vector<int>>&grid,int r,int c){ | |
if( j1<0 || j2<0 || j1>c-1 || j2>c-1 ) return mod; | |
if(i==r-1){ | |
if(j1==j2) return grid[i][j1]; | |
else{ | |
return grid[i][j1]+grid[i][j2]; | |
} | |
} | |
if(dp[i][j1][j2]!=-1) return dp[i][j1][j2]; | |
int maxi=0; | |
// for each alice and bob there are 3 direction so in total ther are 9 direction | |
for(int dj1=-1;dj1<=1;dj1++){ | |
for(int dj2=-1;dj2<=1;dj2++){ | |
if(j1==j2){ | |
maxi=max(maxi,grid[i][j1]+solve(i+1,j1+dj1,j2+dj2,grid,r,c)); | |
} | |
else{ | |
maxi=max(maxi,grid[i][j1]+grid[i][j2]+solve(i+1,j1+dj1,j2+dj2,grid,r,c)); | |
} | |
} | |
} | |
return dp[i][j1][j2]=maxi; | |
} | |
int maximumChocolates(int r, int c, vector<vector<int>> &grid) { | |
// Write your code here. | |
memset(dp,-1,sizeof dp); | |
return solve(0,0,c-1,grid,r,c); | |
} |
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