Created
October 7, 2015 15:18
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Simple wins this round. forEach doesn't help with anything except obfuscation.
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| for 🔢 in 1...100{print([3:"Fi",5:"Bu"].reduce(nil){🔢%$1.0==0 ?$1.1+"zz"+($0 ?? ""):$0} ?? 🔢)} //93 | |
| for 🔢 in 1...100{print(🔢%15==0 ?"FizzBuzz":🔢%3==0 ?"Fizz":🔢%5==0 ?"Buzz":"\(🔢)")} //81 | |
| (1...100).forEach{print($0%15==0 ?"FizzBuzz":$0%3==0 ?"Fizz":$0%5==0 ?"Buzz":"\($0)")} //86 |
No! Can you? I think the smallest number I've seen was 59, but I haven't seen anyone else do it in Swift.
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Do you think with some effort you could get it under 50?