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// LINK TO EXERCISE: https://www.hackerrank.com/challenges/2d-array/problem | |
#include <bits/stdc++.h> | |
using namespace std; | |
// Complete the hourglassSum function below. | |
int hourglassSum(vector<vector<int>> arr) { | |
if (arr.size() < 3 || arr[0].size() < 3) return 0; | |
int maxHourglassSum = numeric_limits<int>::min(); | |
int iterationsRight = arr[0].size() - 2; | |
int iterationsDown = arr.size() - 2; | |
vector<pair<int, int>> indexes {{0, 0}, {0, 1}, {0, 2}, | |
{1, 1}, | |
{2, 0}, {2, 1}, {2, 2}}; | |
auto movePatternRight = [](pair<int, int>& p) { | |
get<1>(p) += 1; | |
}; | |
auto movePatternDownAndLeft = [](pair<int, int>& p) { | |
get<1>(p) -= 3; | |
get<0>(p) += 1; | |
}; | |
for (int i = 0; i < iterationsDown; ++i) { | |
for (int j = 0; j < iterationsRight; ++j) { | |
// Calculating sum of hourglasses | |
int sum = accumulate(indexes.cbegin(), indexes.cend(), 0, | |
[&arr](int res, pair<int, int> p){ | |
return move(res) + arr[get<0>(p)][get<1>(p)]; | |
}); | |
if (maxHourglassSum < sum) maxHourglassSum = sum; | |
if (j == iterationsRight - 1) break; // Don't move last time | |
for_each(indexes.begin(), indexes.end(), movePatternRight); | |
} | |
for_each(indexes.begin(), indexes.end(), movePatternDownAndLeft); | |
} | |
return maxHourglassSum; | |
} | |
int main() | |
{ | |
ofstream fout(getenv("OUTPUT_PATH")); | |
vector<vector<int>> arr(6); | |
for (int i = 0; i < 6; i++) { | |
arr[i].resize(6); | |
for (int j = 0; j < 6; j++) { | |
cin >> arr[i][j]; | |
} | |
cin.ignore(numeric_limits<streamsize>::max(), '\n'); | |
} | |
int result = hourglassSum(arr); | |
fout << result << "\n"; | |
fout.close(); | |
return 0; | |
} |
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