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June 23, 2020 13:06
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Write a program that prints the next 20 leap years.
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| # Input | |
| CURRENT_YEAR = 2017 | |
| NOF_LEAP_YEARS = 20 | |
| # Functions | |
| def is_leap_year(year): | |
| if year % 4 > 0: | |
| return False | |
| elif year % 100 > 0: | |
| return True | |
| elif year % 400 > 0: | |
| return False | |
| else: | |
| return True | |
| def print_next_leap_years(current_year, nof_leap_years): | |
| nof_leap_years_found = 0 | |
| while nof_leap_years_found < nof_leap_years: | |
| if is_leap_year(current_year): | |
| nof_leap_years_found += 1 | |
| print(current_year) | |
| current_year += 1 | |
| def print_next_leap_years_with_recursion(current_year, nof_leap_years, nof_leap_years_found = 0): | |
| if is_leap_year(current_year): | |
| nof_leap_years_found += 1 | |
| print(current_year) | |
| if nof_leap_years_found < nof_leap_years: | |
| print_next_leap_years_with_recursion(current_year + 1, nof_leap_years, nof_leap_years_found) | |
| # Main | |
| print_next_leap_years(CURRENT_YEAR, NOF_LEAP_YEARS) | |
| print_next_leap_years_with_recursion(CURRENT_YEAR, NOF_LEAP_YEARS) | |
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Cool! Try Lua for a challenge... ;)