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June 18, 2021 23:09
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Get the middle element. If it's an even number of elements, average the middle two values.
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| #Write your function here | |
| def middle_element(lst): | |
| if len(lst) % 2 == 0: | |
| sum = lst[int(len(lst)/2)] + lst[int(len(lst) / 2) - 1] | |
| return sum / 2 | |
| else: | |
| return lst[int(len(lst)/2)] | |
| #Uncomment the line below when your function is done | |
| print(middle_element([5, 2, -10, -4, 4, 5])) | |
| print(middle_element([5, 2, -4, 4, 5])) |
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This one doesn't work because the middle element of an odd count is not an integer.