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December 20, 2015 14:19
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http://zariski.wordpress.com/2013/08/02/%EC%98%A4%EB%8A%98%EC%9D%98-%EB%B8%8C%EB%A0%88%EC%9D%B8%ED%8B%B0%EC%A0%80/ 문제를 확인하기 위한 코드. 결과적으로 35개의 3으로 이루어진 목록은 나오지만 최종적으로 1만으로 이루어진 데까지는 가지 않는다.
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| # -*- coding:utf-8 -*- | |
| from itertools import combinations | |
| from pprint import pprint | |
| bundle = [51,49,5] | |
| candidates = [bundle] | |
| loop = True | |
| loop_count = 0 | |
| largest_member = [] | |
| while loop: | |
| loop_count = loop_count + 1 | |
| max_number_of_members = 0 | |
| max_member = 0 | |
| #if len(largest_member) > 33: candidates = [largest_member] | |
| #print candidates | |
| for i,b in enumerate(candidates): | |
| splitable = False | |
| if max_number_of_members < len(b): | |
| max_number_of_members = len(b) | |
| largest_member = b | |
| # 나눌 수 있으면 | |
| for key,val in enumerate(b): | |
| if val % 2 == 0: | |
| splitable = True | |
| # 현재 묶음은 제거 | |
| del candidates[i][key] | |
| # 나눈 값으로 새 묶음 생성 | |
| candidates[i].append(val/2) | |
| candidates[i].append(val/2) | |
| candidates[i].sort() | |
| if max_member < max(candidates[i]): | |
| max_member = max(candidates[i]) | |
| # 나눌 수 없었으면 | |
| if splitable == False: | |
| # 합해서 다른 묶음 생성 | |
| for c in combinations(b,2): | |
| _b = list(b) | |
| _b.remove(c[0]) | |
| _b.remove(c[1]) | |
| _b.append(c[0] + c[1]) | |
| _b.sort() | |
| candidates.append(_b) | |
| # 현재 묶음은 제거 | |
| del candidates[i] | |
| candidates = reduce(lambda x, y: x if y in x else x + [y], candidates, []) | |
| pprint(candidates) | |
| print len(candidates), max_number_of_members, max_member, largest_member | |
| if loop_count >= 1000: | |
| loop = False | |
| if len(candidates) == 0: | |
| loop = False | |
| if max_number_of_members == 1: | |
| loop = False |
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