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July 18, 2019 06:55
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| /*Intermediate Algorithm Scripting: Arguments Optional | |
| Create a function that sums two arguments together. If only one argument is provided, then return a function that expects one argument and returns the sum. | |
| For example, addTogether(2, 3) should return 5, and addTogether(2) should return a function. | |
| Calling this returned function with a single argument will then return the sum: | |
| var sumTwoAnd = addTogether(2); | |
| sumTwoAnd(3) returns 5. | |
| If either argument isn't a valid number, return undefined. | |
| https://learn.freecodecamp.org/javascript-algorithms-and-data-structures/intermediate-algorithm-scripting/arguments-optional/ | |
| https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Operators/Conditional_Operator*/ | |
| function addTogether() { | |
| let args = []; | |
| for (let i=0; i< arguments.length; i++){ | |
| args[i] = arguments[i]; | |
| } | |
| //if we have two (or more) arguments, add first two, if both numbers, else return undefined. Else return a function, if both nums, else undefined | |
| if (args.length > 1) { | |
| return (typeof args[0] === 'number' && typeof args[1] === 'number' ? args[0] + args[1] : undefined); | |
| } else if (args.length === 1) { | |
| return (typeof args[0] === 'number' ? | |
| function(num) { | |
| return (typeof num === 'number' ? args[0] + num : undefined); | |
| } | |
| : undefined) | |
| } | |
| } | |
| addTogether(2,3); | |
| /* | |
| addTogether(2, 3) should return 5. | |
| Passed | |
| addTogether(2)(3) should return 5. | |
| Passed | |
| addTogether("http://bit.ly/IqT6zt") should return undefined. | |
| Passed | |
| addTogether(2, "3") should return undefined. | |
| Passed | |
| addTogether(2)([3]) should return undefined. | |
| Passed | |
| */ |
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